来自郭凤梅的问题
解方程组:(1)x=y−23x−2y=−1;(2)2x+3y=−11①6x−5y=9②.
解方程组:
(1)
x=y−23x−2y=−1;
(2)
2x+3y=−11①6x−5y=9②.
1回答
2020-03-07 05:24
解方程组:(1)x=y−23x−2y=−1;(2)2x+3y=−11①6x−5y=9②.
解方程组:
(1)
x=y−23x−2y=−1;
(2)
2x+3y=−11①6x−5y=9②.
(1)
x=y−2①3x−2y=−1②