来自丁克勤的问题
一道数学题,急...根据规律,解方程1/(x-4)(x-3)+1/(x-3)(x-2)+1/(x-2)(x-1)+1/(x-1)x=1/x(x+1)=1/x+11/2=1/1*2=1-1/21/6=1/2*3=1/2-1/31/12=1/3*4=1/3-1/41/20=1/4*5=1/4-1/5请利用上述规律,解方程1/(x-4)(x-3)+1/(x-3)(x-2)+1/(x-2)(x-1)+
一道数学题,急...
根据规律,解方程
1/(x-4)(x-3)+1/(x-3)(x-2)+1/(x-2)(x-1)+1/(x-1)x=1/x(x+1)=1/x+1
1/2=1/1*2=1-1/2
1/6=1/2*3=1/2-1/3
1/12=1/3*4=1/3-1/4
1/20=1/4*5=1/4-1/5
请利用上述规律,解方程
1/(x-4)(x-3)+1/(x-3)(x-2)+1/(x-2)(x-1)+1/(x-1)x=1/x(x+1)=1/x+1
1回答
2020-03-10 20:53