一道数学题,急...根据规律,解方程1/(x-4)(x-3)-查字典问答网
分类选择

来自丁克勤的问题

  一道数学题,急...根据规律,解方程1/(x-4)(x-3)+1/(x-3)(x-2)+1/(x-2)(x-1)+1/(x-1)x=1/x(x+1)=1/x+11/2=1/1*2=1-1/21/6=1/2*3=1/2-1/31/12=1/3*4=1/3-1/41/20=1/4*5=1/4-1/5请利用上述规律,解方程1/(x-4)(x-3)+1/(x-3)(x-2)+1/(x-2)(x-1)+

  一道数学题,急...

  根据规律,解方程

  1/(x-4)(x-3)+1/(x-3)(x-2)+1/(x-2)(x-1)+1/(x-1)x=1/x(x+1)=1/x+1

  1/2=1/1*2=1-1/2

  1/6=1/2*3=1/2-1/3

  1/12=1/3*4=1/3-1/4

  1/20=1/4*5=1/4-1/5

  请利用上述规律,解方程

  1/(x-4)(x-3)+1/(x-3)(x-2)+1/(x-2)(x-1)+1/(x-1)x=1/x(x+1)=1/x+1

1回答
2020-03-10 20:53
我要回答
请先登录
李文哲

  改为

  ……+1/(x-1)x+1/x(x+1)=1/(x+1)

  1/(x-4)(x-3)=1/(x-4)-1/(x-3)

  1/(x-3)(x-2)=1/(x-3)-1/(x-2)

  ……

  1/(x-4)-1/(x-3)+1/(x-3)-1/(x-2)+1/(x-2)-1/(x-1)+1/(x-1)-1/x+1/x-1/(x+1)=1/(x+1)

  1/(x-4)-1/(x+1)=1/(x+1)

  1/(x-4)=2/(x+1)

  x+1=2x-8

  x=9

2020-03-10 20:57:18

最新问答

推荐文章

猜你喜欢

附近的人在看

推荐阅读

拓展阅读

  • 大家都在看
  • 小编推荐
  • 猜你喜欢
  •