【y=sinx求导y=sinx⊿y=sin(x+⊿x)-sinx=2cos(x+⊿x/2)sin(⊿x/2)⊿y/⊿x=2cos(x+⊿x/2)sin(⊿x/2)/⊿x=cos(x+⊿x/2)sin(⊿x/2)/(⊿x/2)所以lim⊿x→0⊿y/⊿x=lim⊿x→0cos(x+⊿x/2)•lim⊿x→0sin(⊿x/2)/(⊿x/2)=cosx第一】

　　y=sinx求导

　　y=sinx

　　⊿y=sin(x+⊿x)-sinx=2cos(x+⊿x/2)sin(⊿x/2)

　　⊿y/⊿x=2cos(x+⊿x/2)sin(⊿x/2)/⊿x=cos(x+⊿x/2)sin(⊿x/2)/(⊿x/2)

　　所以lim⊿x→0⊿y/⊿x=lim⊿x→0cos(x+⊿x/2)•lim⊿x→0sin(⊿x/2)/(⊿x/2)=cosx

　　第一步⊿y=sin(x+⊿x)-sinx=2cos(x+⊿x/2)sin(⊿x/2)

　　没看明白求解释