化简无理指数幂.主要是思路啊大侠们遇到这种题如何插手啊化简(-查字典问答网
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  化简无理指数幂.主要是思路啊大侠们遇到这种题如何插手啊化简(X+Y)/(X^(1/3)+Y^(1/3))-(X^(4/3)-Y^(4/3))/(X^(2/3)-Y^(2/3))咋做啊

  化简无理指数幂.主要是思路啊大侠们遇到这种题如何插手啊

  化简(X+Y)/(X^(1/3)+Y^(1/3))-(X^(4/3)-Y^(4/3))/(X^(2/3)-Y^(2/3))咋做啊

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2020-03-17 19:56
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邱忠义

  第一个乘X^(1/3)-Y^(1/3)就行了--

  (X+Y)/(X^(1/3)+Y^(1/3))-(X^(4/3)-Y^(4/3))/(X^(2/3)-Y^(2/3))

  =(X+Y)(X^(1/3)-Y^(1/3))/(X^(1/3)+Y^(1/3))(X^(1/3)-Y^(1/3))-(X^(4/3)-Y^(4/3))/(X^(2/3)-Y^(2/3))

  =(X+Y)(X^(1/3)-Y^(1/3))/(X^(2/3)-Y^(2/3))-(X^(4/3)-Y^(4/3))/(X^(2/3)-Y^(2/3))

  =[(X+Y)(X^(1/3)-Y^(1/3))-(X^(4/3)-Y^(4/3))]/(X^(2/3)-Y^(2/3))

  =[(X^(4/3)-XY^(1/3)+X^(1/3)Y-Y^(4/3)-X^(4/3)+Y^(4/3)]/(X^(2/3)-Y^(2/3))

  =(X^(1/3)Y-XY^(1/3))/(X^(2/3)-Y^(2/3))

  =(X^(1/3)Y-XY^(1/3))(X^(4/3)+X^(2/3)Y^(2/3)+Y^(4/3))/(X^(2/3)-Y^(2/3))(X^(4/3)+X^(2/3)Y^(2/3)+Y^(4/3))

  =(X^(1/3)Y-XY^(1/3))(X^(4/3)+X^(2/3)Y^(2/3)+Y^(4/3))/(X^2-Y^2)

  =(X^(5/3)Y+XY^(5/3)+X^(1/3)Y^(7/3)-X^(7/3)Y^(1/3)-X^(5/3)Y-XY^(5/3))/(X^2-Y^2)

2020-03-17 20:00:40

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