来自胡德发的问题
设函数f(x)=x2+aln(x+1)(a为常数)(Ⅰ)若函数y=f(x)在区间[1,+∞)上是单凋递增函数,求实数a的取值范围;(Ⅱ)若函数y=f(x)有两个极值点x1,x2,且x1<x2,求证:0<f(x2)x1<−12
设函数f(x)=x2+aln(x+1)(a为常数)
(Ⅰ)若函数y=f(x)在区间[1,+∞)上是单凋递增函数,求实数a的取值范围;
(Ⅱ)若函数y=f(x)有两个极值点x1,x2,且x1<x2,求证:0<f(x2)x1<−12+ln2.
1回答
2020-03-19 19:35