来自孙玉芬的问题
设函数f(x)=1-e-x.(Ⅰ)证明:当x>-1时,f(x)≥xx+1;(Ⅱ)设当x≥0时,f(x)≤xax+1,求a的取值范围.
设函数f(x)=1-e-x.
(Ⅰ)证明:当x>-1时,f(x)≥xx+1;
(Ⅱ)设当x≥0时,f(x)≤xax+1,求a的取值范围.
1回答
2020-03-19 05:53
设函数f(x)=1-e-x.(Ⅰ)证明:当x>-1时,f(x)≥xx+1;(Ⅱ)设当x≥0时,f(x)≤xax+1,求a的取值范围.
设函数f(x)=1-e-x.
(Ⅰ)证明:当x>-1时,f(x)≥xx+1;
(Ⅱ)设当x≥0时,f(x)≤xax+1,求a的取值范围.
(1)当x>-1时,f(x)≥xx+1