来自丁汝才的问题
0.3x²+x=0.8x²+3=2√3xx²+2x-2=03x²+4x-7=0
0.3x²+x=0.8x²+3=2√3xx²+2x-2=03x²+4x-7=0
1回答
2020-03-22 05:30
0.3x²+x=0.8x²+3=2√3xx²+2x-2=03x²+4x-7=0
0.3x²+x=0.8x²+3=2√3xx²+2x-2=03x²+4x-7=0
0.3x²+x=0.8
3x²+10x=8
(3x+5)²=49
3x+5=±7
x=-4或2/3
x²+3=2√3x
x²-2√3x+3=0
(x-√3)²=0
x=√3
x²+2x-2=0
(x+1)²=3
x+1=±√3
x=±√3-1
3x²+4x-7=0
(3x+2)²=11
3x+2=±√11
x=(±√11-2)/3