来自贾激雷的问题
二元一次方程组的题(1){2y-3(1-2x)=13(2){1/2x+3y=2/3(3){x/3+y/4=1/6(4){2x-1/5+3y-2/4=2{2x=3(y-1)+1{x-3/4y=-29/12{1/2x-5/4y=-3{3x+1/5-3y+2/4=0(5){x-1/2+y-2/3=2(6){x-1/2+y-2/3=2{3x+1/5+3y+2/4=0{3x-5/4-y-2/2=-1/2
二元一次方程组的题
(1){2y-3(1-2x)=13(2){1/2x+3y=2/3(3){x/3+y/4=1/6(4){2x-1/5+3y-2/4=2
{2x=3(y-1)+1{x-3/4y=-29/12{1/2x-5/4y=-3{3x+1/5-3y+2/4=0
(5){x-1/2+y-2/3=2(6){x-1/2+y-2/3=2
{3x+1/5+3y+2/4=0{3x-5/4-y-2/2=-1/2
3回答
2020-03-24 10:59