来自曹靖的问题
3(2^2+1)(2^4+1)(2^8+1)…(2^128+1)+1=?
3(2^2+1)(2^4+1)(2^8+1)…(2^128+1)+1=?
1回答
2020-03-24 07:59
3(2^2+1)(2^4+1)(2^8+1)…(2^128+1)+1=?
3(2^2+1)(2^4+1)(2^8+1)…(2^128+1)+1=?
3=2^2-1
代入3(2^2+1)(2^4+1)(2^8+1)…(2^128+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)…(2^128+1)+1
=(2^4-1)(2^4+1)(2^8+1)…(2^128+1)+1
.
.
=(2^128-1)(2^128+1)+1
=(2^128)²-1+1
=2^256