来自蒋明刚的问题
计算:3a²*a²+2a*a²*a²-4a²*a²
计算:3a²*a²+2a*a²*a²-4a²*a²
3回答
2020-03-24 06:34
计算:3a²*a²+2a*a²*a²-4a²*a²
计算:3a²*a²+2a*a²*a²-4a²*a²
3a^2*a^2+2a*a^2*a^2-4a^2*a^2=3a^4+2a^5-4a^4=2a^5-a^4=a^4*(2a-1)
3a²*a^4+2a*a²*a²-4a^5*a²我会加分
=3a^6+2a^5-4a^7=a^5*(-4a^2+3a+2)