来自郭东辉的问题
3a^2x^3/(1/3ax)*(-4a^5x^3)/(6a^2x^5)
3a^2x^3/(1/3ax)*(-4a^5x^3)/(6a^2x^5)
1回答
2020-03-26 19:41
3a^2x^3/(1/3ax)*(-4a^5x^3)/(6a^2x^5)
3a^2x^3/(1/3ax)*(-4a^5x^3)/(6a^2x^5)
3a^2x^3/(1/3ax)*(-4a^5x^3)/(6a^2x^5)
=9ax^2*(-2a^3/3x^2)
=-6a^4