来自冯国聪的问题
2道数学题,快(1)2^5*x=2^8,则x=(2)需过程,解方程:(x+2)(x-3)-(x-4)(2x+3)=6-x^2
2道数学题,快
(1)2^5*x=2^8,则x=
(2)需过程,解方程:(x+2)(x-3)-(x-4)(2x+3)=6-x^2
1回答
2020-03-30 14:12
2道数学题,快(1)2^5*x=2^8,则x=(2)需过程,解方程:(x+2)(x-3)-(x-4)(2x+3)=6-x^2
2道数学题,快
(1)2^5*x=2^8,则x=
(2)需过程,解方程:(x+2)(x-3)-(x-4)(2x+3)=6-x^2
(1)x=2^3=8
(2)展开得:x^2-x-6-2x^2+8x-3x+12=6-x^2
4x=0
x=0