来自黄夏兰的问题
【初二数学分式化简已知x-3y=0(xy不等于0),求【(2x+y)/(x²-2xy+y²)】*(x-y)的值先化简,在带入】
初二数学分式化简
已知x-3y=0(xy不等于0),求【(2x+y)/(x²-2xy+y²)】*(x-y)的值
先化简,在带入
1回答
2020-03-30 22:35
【初二数学分式化简已知x-3y=0(xy不等于0),求【(2x+y)/(x²-2xy+y²)】*(x-y)的值先化简,在带入】
初二数学分式化简
已知x-3y=0(xy不等于0),求【(2x+y)/(x²-2xy+y²)】*(x-y)的值
先化简,在带入
原式=(2x+y)/(x-y)
x-3y=0所以x=3y
代入得
原式=(6y+y)/(3y-y)
=7y/2y
=7/2