来自卢道全的问题
初二数学分式计算1/(x-3)-6/(x2-9)-(x-1)/(6+2x)
初二数学分式计算
1/(x-3)-6/(x2-9)-(x-1)/(6+2x)
1回答
2020-03-31 00:05
初二数学分式计算1/(x-3)-6/(x2-9)-(x-1)/(6+2x)
初二数学分式计算
1/(x-3)-6/(x2-9)-(x-1)/(6+2x)
1/(x-3)-6/(x2-9)-(x-1)/(6+2x)
=1/(x-3)-6/[(x+3)(x-3)]-(x-1)/[2(x+3)]
=[2x+6-6*2-(x-1)*(x-3)]/[2(x+3)(x-3)]
=(3-x)/(6+2x)