来自唐小静的问题
【求证logaM/N=logaM-logaN】
求证logaM/N=logaM-logaN
1回答
2020-04-05 15:40
【求证logaM/N=logaM-logaN】
求证logaM/N=logaM-logaN
设a^x=M,a^y=N
M/N=(a^x)/(a^y)=a^(x-y)
loga(M/N)=logaa^(x-y)=x-y
logaM-logaN=x-y
所以loga(M/N)=logaM-logaN