来自李培根的问题
求对数函数公式的推导log(a)(M^n)=nlog(a)(M)和log(a)(N)=log(b)(N)/log(b)(a)的推导
求对数函数公式的推导
log(a)(M^n)=nlog(a)(M)
和log(a)(N)=log(b)(N)/log(b)(a)的推导
1回答
2020-04-05 09:47
求对数函数公式的推导log(a)(M^n)=nlog(a)(M)和log(a)(N)=log(b)(N)/log(b)(a)的推导
求对数函数公式的推导
log(a)(M^n)=nlog(a)(M)
和log(a)(N)=log(b)(N)/log(b)(a)的推导
log(a)(M^n)
=log(a)(M*M*M*..M)(n个M)
=log(a)(M)+log(a)(M)+log(a)(M)+.+log(a)(M)(n个log(a)(M))
=nlog(a)(M)
log(a)(N)
=log(a)[b^log(b)(N)]
=log(b)(N)log(a)(b)
=log(b)(N)log(a)(a^log(b)(a))
=log(b)(N)/log(b)(a)