来自高利军的问题
logam/n=logam-logan
logam/n=logam-logan
1回答
2020-04-08 18:42
logam/n=logam-logan
logam/n=logam-logan
1、因为n=log(a)(b),代入则a^n=b,即a^(log(a)(b))=b.
2、MN=M×N由基本性质1(换掉M和N)a^[log(a)(MN)]=a^[log(a)(M)]×a^[log(a)(N)]由指数的性质a^[log(a)(MN)]=a^{[log(a)(M)]+[log(a)(N)]}又因为指数函数是单调函数,所以log(a)(MN)=log(a)(M)+log(a)(N)
3、与(2)类似处理MN=M÷N由基本性质1(换掉M和N)a^[log(a)(M/N)]=a^[log(a)(M)]÷a^[log(a)(N)]由指数的性质a^[log(a)(M/N)]=a^{[log(a)(M)]-[log(a)(N)]}又因为指数函数是单调函数,所以log(a)(M/N)=log(a)(M)-log(a)(N)
时间比较晚了,我直接给你拉答案过来了,我就不自己打了