来自季新宝的问题
1.(1/2)^-2+(1/4)^0+(1/2)^-3===2.(-1/3)^-2+(-2又2/3)÷{2^-3x[2-(-2/3)^-2}===3.已知5x-3y+2=0,求10^5x÷10^3y的值
1.(1/2)^-2+(1/4)^0+(1/2)^-3
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2.(-1/3)^-2+(-2又2/3)÷{2^-3x[2-(-2/3)^-2}
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3.已知5x-3y+2=0,求10^5x÷10^3y的值
1回答
2020-04-10 12:58