数值分析上机题,给定方程组,即AX=b1.分别用列主元消去法和追赶法解上述三对角方程组AX=b.2.讨论当b有微小变化,即b+b=(1.01,0.01,0.05,0.00,0.00)时,A是否为病态矩阵.给出讨论结果.3.输出
数值分析上机题,
给定方程组
,即AX=b
1.分别用列主元消去法和追赶法解上述三对角方程组AX=b.
2.讨论当b有微小变化,即b+b=(1.01,0.01,0.05,0.00,0.00)时,A是否为病态矩阵.给出讨论结果.
3.输出分解矩阵L,U及解向量X和|A|.
4.对两种计算结果加以比较.
最好给下程序
程序设计流程图
|2-1000|x1|1|
|-12-100|x2|0|
|0-12-10|x3=|0|
|00-12-1|x4|0|
|000-12|x5|0|
谢谢这位大哥了阿!
我给你发我的题了你帮我在看看!