来自李沛秦的问题
利用因式分解求x+3y=125(x≠y)时,(x2+2xy-3y2)÷(x-y)的值.
利用因式分解求x+3y=125(x≠y)时,(x2+2xy-3y2)÷(x-y)的值.
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2020-04-12 00:42
利用因式分解求x+3y=125(x≠y)时,(x2+2xy-3y2)÷(x-y)的值.
利用因式分解求x+3y=125(x≠y)时,(x2+2xy-3y2)÷(x-y)的值.
∵x+3y=125,
∴(x2+2xy-3y2)÷(x-y)=(x-y)(x+3y)÷(x-y)=x+3y=125.