来自柴干的问题
sin(2x+π/3）-根号3sin(2x+5π/6）怎么算?
sin(2x+π/3）-根号3sin(2x+5π/6）怎么算?
1回答
2020-04-14 12:04
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陈明华
sin(2x+π/3）-√3sin(2x+5π/6﹚
＝sin(2x+π/3）＋√3sin﹙2x－π／6﹚
＝sin(2x+π/3）-√3cos﹙2x+π/3﹚
＝2[½sin(2x+π/3）－√3／2cos﹙2x+π/3﹚]
＝2sin2x
2020-04-14 12:07:47