来自陈忠明的问题
若函数f(x)=13x3+12f′(1)x2-f′(2)x+3,则f(x)在点(0,f(0))处切线的倾斜角为()A.π4B.π3C.2π3D.34π
若函数f(x)=13x3+12f′(1)x2-f′(2)x+3,则f(x)在点(0,f(0))处切线的倾斜角为()
A.π4
B.π3
C.2π3
D.34π
1回答
2020-04-24 21:44
若函数f(x)=13x3+12f′(1)x2-f′(2)x+3,则f(x)在点(0,f(0))处切线的倾斜角为()A.π4B.π3C.2π3D.34π
若函数f(x)=13x3+12f′(1)x2-f′(2)x+3,则f(x)在点(0,f(0))处切线的倾斜角为()
A.π4
B.π3
C.2π3
D.34π
解析:由题意得:f′(x)=x2+f′(1)x-f′(2),
令x=0,得f′(0)=-f′(2),
令x=1,得f′(1)=1+f′(1)-f′(2),
∴f′(2)=1,∴f′(0)=-1,
即f(x)在点(0,f(0))处切线的斜率为-1,
∴倾斜角为34