当x∈[-6,-2/3]时,判断函数y=fx+f(x+2)的-查字典问答网
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来自高世一的问题

  当x∈[-6,-2/3]时,判断函数y=fx+f(x+2)的单调性fx=2sin(π/4x+π/4)我想看将fx带入后化简的步骤~

  当x∈[-6,-2/3]时,判断函数y=fx+f(x+2)的单调性

  fx=2sin(π/4x+π/4)我想看将fx带入后化简的步骤~

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2020-04-24 20:25
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刘纪芹

  f(x)=2sin(π/4x+π/4)

  y=f(x)+f(x+2)

  =2sin(π/4x+π/4)+2sin[π/4(x+2)+π/4]

  =2sin(π/4x+π/4)+2sin[π/4x+π/2+π/4]

  =2sin(π/4x+π/4)+2cos(π/4x+π/4)

  =2√2[√√2/2*sin(π/4x+π/4)+√2/2*cos(π/4x+π/4)]

  =2√2sin[(π/4*x+π/4)+π/4]

  =2√2sin(π/4*x+π/2)

  =2√2cos(π/4*x)

  ∵x∈[-6,-2/3]

  ∴-3π/2≤π/4x≤-π/6

  ∴当-3π/2≤π/4x≤-π,即x∈[-6,-4]时,函数递减,

  当-π≤π/4x≤-π/6,即x∈[-4,-2/3]时,函数递增

2020-04-24 20:30:17

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