来自董玉华的问题
计算:[(3a-2b)^2-(3a+2b)(3a-2b)]÷(2b-3a)
计算:[(3a-2b)^2-(3a+2b)(3a-2b)]÷(2b-3a)
1回答
2020-04-26 08:57
计算:[(3a-2b)^2-(3a+2b)(3a-2b)]÷(2b-3a)
计算:[(3a-2b)^2-(3a+2b)(3a-2b)]÷(2b-3a)
原式=(3a-2b)[(3a-2b)-(3a+2b)]÷(2b-3a)
=-4b(3a-2b)÷(2b-3a)=4b