换底公式log(a)(N)=log(b)(N)/log(b)(a)推导如下：

　　N=a^[log(a)(N)]a=b^[log(b)(a)]综合两式可得N={b^[log(b)(a)]}^[log(a)(N)]=b^{[log(a)(N)]*[log(b)(a)]}又因为N=b^[log(b)(N)]所以b^[log(b)(N)]=b^{[log(a)(N)]*[log(b)(a)]}所以log(b)(N)=[log(a)(N)]*[log(b)(a)]所以log(a)(N)=log(b)(N)/log(b)(a)