【1.(2a^2b)·(-1/2ab^2)^32.(-2/5-查字典问答网
分类选择

来自汪先矩的问题

  【1.(2a^2b)·(-1/2ab^2)^32.(-2/5xy^2z)·(-1/2y^2z^2)3.(2x)^3·y^3÷(16xy^2)4.(-a^2b)^4÷(-1/2ab^2)5.-2x^2y(3xy^2z-2y^2z)6.(-2/3a)(1/2a^2+1/6a+1/4)7.(x-3y)(x-1/2y)8.(-a-3b)(7a+2b)9.(9x-2y)(x+y)10.(-1/3p+1/2p)(-2/3p-1/4p)11.(-1/5a^3x^4-9/10a^2x^3)÷(-3/5】

  1.(2a^2b)·(-1/2ab^2)^3

  2.(-2/5xy^2z)·(-1/2y^2z^2)

  3.(2x)^3·y^3÷(16xy^2)

  4.(-a^2b)^4÷(-1/2ab^2)

  5.-2x^2y(3xy^2z-2y^2z)

  6.(-2/3a)(1/2a^2+1/6a+1/4)

  7.(x-3y)(x-1/2y)

  8.(-a-3b)(7a+2b)

  9.(9x-2y)(x+y)

  10.(-1/3p+1/2p)(-2/3p-1/4p)

  11.(-1/5a^3x^4-9/10a^2x^3)÷(-3/5ax^2)

  12.(-2πr^2h+3πrh^2)÷(1/2πrh)

1回答
2020-04-29 04:55
我要回答
请先登录
陈正

  1.(2a^2b)·(-1/2ab^2)^3=2a^2b*(-1/8)a^3b^6=-(1/4)a^5b^72.(-2/5xy^2z)·(-1/2y^2z^2)=(1/5)xy^4z^33.(2x)^3·y^3÷(16xy^2)=8x^3y^3/16xy^2=(1/2)x^2y4.(-a^2b)^4÷(-1/2ab^2)=a^8b^4/(-1/2ab^2)=-(1/2)a^7b^...

2020-04-29 04:58:31

最新问答

推荐文章

猜你喜欢

附近的人在看

推荐阅读

拓展阅读

  • 大家都在看
  • 小编推荐
  • 猜你喜欢
  •