来自惠俊英的问题
(2012•漳州模拟)设双曲线y2a2−x2b2=1(a>0,b>0)的渐近线与圆(x−1)2+(y−1)2=15相切,则该双曲线的离心率等于()A.52或5B.54或53C.5D.53
(2012•漳州模拟)设双曲线y2a2−x2b2=1(a>0,b>0)的渐近线与圆(x−1)2+(y−1)2=15相切,则该双曲线的离心率等于()
A.
52或
5
B.54或53
C.
5
D.53
1回答
2020-05-03 02:07