来自李旭祥的问题
均值不等式解函数f(x)=(x²-x=1)/(x-1)(x>1)f(x)=(x²-x+1)/(x-1)(x>1)打错了
均值不等式解函数
f(x)=(x²-x=1)/(x-1)(x>1)
f(x)=(x²-x+1)/(x-1)(x>1)打错了
3回答
2020-05-04 18:13
均值不等式解函数f(x)=(x²-x=1)/(x-1)(x>1)f(x)=(x²-x+1)/(x-1)(x>1)打错了
均值不等式解函数
f(x)=(x²-x=1)/(x-1)(x>1)
f(x)=(x²-x+1)/(x-1)(x>1)打错了
f(x)=(x²-x)/(x-1)+1/(x-1)
=x+1/(x-1)
=(x-1)+1/(x-1)+1
x>1,x-1>0
所以f(x)≥2√[(x-1)*1/(x-1)]+1=2+1=3
最小值是3
x>1,x-1>0所以f(x)≥2√[(x-1)*1/(x-1)]+1=2+1=3最小值是3这里没看懂
a+b>=2√ab