来自任冬梅的问题
已知x,y,z>0,求证:已知x,y,z>0,求证:(x+y+z)(1/(x+y)+1/(y+z)+1/(z+x))≥9/2,用均值不等式解答!
已知x,y,z>0,求证:
已知x,y,z>0,求证:(x+y+z)(1/(x+y)+1/(y+z)+1/(z+x))≥9/2,用均值不等式解答!
1回答
2020-05-06 22:48
已知x,y,z>0,求证:已知x,y,z>0,求证:(x+y+z)(1/(x+y)+1/(y+z)+1/(z+x))≥9/2,用均值不等式解答!
已知x,y,z>0,求证:
已知x,y,z>0,求证:(x+y+z)(1/(x+y)+1/(y+z)+1/(z+x))≥9/2,用均值不等式解答!
由题.(x+y+z)(1/(x+y)+1/(y+z)+1/(z+x))=1+z/x+y+1+x/y+z+1+y/z+x
=3+3(开3次方)√xyz/(x+y)(y+z)(x+z)
≥3+3(开3次方)√xyz/8xyz
=3+3x1/2=9/2
当且仅当x=y=z时成立