来自白跃彬的问题
一根绳子,剪去13后还剩12米,这根绳子原来长多少米?列式为()A.12+13B.12÷(1−13)C.12+12×13D.12÷13
一根绳子,剪去13后还剩12米,这根绳子原来长多少米?列式为()
A.12+13
B.12÷(1−13)
C.12+12×13
D.12÷13
1回答
2020-05-14 23:25
一根绳子,剪去13后还剩12米,这根绳子原来长多少米?列式为()A.12+13B.12÷(1−13)C.12+12×13D.12÷13
一根绳子,剪去13后还剩12米,这根绳子原来长多少米?列式为()
A.12+13
B.12÷(1−13)
C.12+12×13
D.12÷13
12