来自李传湘的问题
【初一乘法公式1.求证:(x+y-2z)^3+(y+z-2x)^3+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)2.在括号里填上适当的数或式,使等式成立(1)x^2-1/2x+()=(x-1/4)^2(2)(a+b)^2+()=(a-b)^2(3)(1/2x-4)[1/4x^2+()+16]=()^3-()^33.解方程.(5x+7)(5x-7)+(x】
初一乘法公式
1.求证:(x+y-2z)^3+(y+z-2x)^3+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
2.在括号里填上适当的数或式,使等式成立
(1)x^2-1/2x+()=(x-1/4)^2(2)(a+b)^2+()=(a-b)^2
(3)(1/2x-4)[1/4x^2+()+16]=()^3-()^3
3.解方程.(5x+7)(5x-7)+(x+3)^2=10x^2-(4x+1)(-4x-1)+48
4.已知:(-4x+3y)(-3y-4x)减去多项式M的差为-36y^2+5xy,求M
5.已知:a+b+c=0,a^3+b^3+c^3=0求证a^19+b^19+c^19+0
1回答
2020-05-14 12:22