来自邱忠义的问题
解方程:Cx−2x+2+Cx−3x+2=110A3x+3.
解方程:Cx−2
x+2
+Cx−3
x+2
=110A3
x+3
.
1回答
2020-05-15 01:47
解方程:Cx−2x+2+Cx−3x+2=110A3x+3.
解方程:Cx−2
x+2
+Cx−3
x+2
=110A3
x+3
.
∵Cx−2x+2+Cx−3x+2=110A3x+3,∴(x+2)!(x−2)!•[(x+2)−(x−2)]!+(x+2)!(x−3)!•[(x+2)−(x−3)]!=110•(x+3)!(x+3−3)!,∴(x+2)!4!•(x−2)(x−3)!+(x+2)!5!•(x−3)!=110•(x+3)(x+2)!x(x−1)(x−2)(x−3)!...