来自蔡曦的问题
5(10/x+10/(x+3/5)=125
5(10/x+10/(x+3/5)=125
1回答
2020-05-14 19:57
5(10/x+10/(x+3/5)=125
5(10/x+10/(x+3/5)=125
5(10/x+10/(x+3/5)=125
两边除以5
10/x+10/(x+3/5)=25
再除以5
2/x+2/(x+3/5)=5
即
2/x+10/(5x+3)=5
去分母:
2(5x+3)+10x=5x(5x+3)
10x+6+10x=25x^2+15x
25x^2-5x-6=0
所以(5x+2)(5x-3)=0
所以x1=-2/5,x2=3/5
经检验,x1=-2/5,x2=3/5都是原方程的根
所以原方程的解是
x1=-2/5,x2=3/5