来自戴维的问题
已知6x-1=2,2y+3=5,求(5x²y+5xy-7y)-(4x²y+5xy-7x)的值.好的追分哦!
已知6x-1=2,2y+3=5,求(5x²y+5xy-7y)-(4x²y+5xy-7x)的值.好的追分哦!
1回答
2020-05-15 01:44
已知6x-1=2,2y+3=5,求(5x²y+5xy-7y)-(4x²y+5xy-7x)的值.好的追分哦!
已知6x-1=2,2y+3=5,求(5x²y+5xy-7y)-(4x²y+5xy-7x)的值.好的追分哦!
6x-1=2,x=1/2
2y+3=5,y=1
(5x²y+5xy-7y)-(4x²y+5xy-7x)
=x²y-7y+7x
=1/4*1-7*1+7*1/2
=(1-4*7-7*2)/4
=-13/4