来自片锦香的问题
(3x+2y-5)²与丨5x+3y-8丨互为相反数,x等于几y等于几是不是题出错了啊我想了半天也做不来
(3x+2y-5)²与丨5x+3y-8丨互为相反数,x等于几y等于几
是不是题出错了啊我想了半天也做不来
1回答
2020-05-16 11:44
(3x+2y-5)²与丨5x+3y-8丨互为相反数,x等于几y等于几是不是题出错了啊我想了半天也做不来
(3x+2y-5)²与丨5x+3y-8丨互为相反数,x等于几y等于几
是不是题出错了啊我想了半天也做不来
(3x+2y-5)²与丨5x+3y-8丨互为相反数,
则(3x+2y-5)²+丨5x+3y-8丨=0
因为(3x+2y-5)²≥0,丨5x+3y-8丨≥0
所以3x+2y-5=0,①
5x+3y-8=0②
①×3-②×2,得9x-15-10x+16=0,解得x=1
代入①,解得y=1