来自huhe的问题
看首尾两个式子,即f[sin(π/2-x)]=sin17(π/2-x);再整体考虑,令t=π/2-x
看首尾两个式子,即f[sin(π/2-x)]=sin17(π/2-x);再整体考虑,令t=π/2-x
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2016-05-21 12:36
看首尾两个式子,即f[sin(π/2-x)]=sin17(π/2-x);再整体考虑,令t=π/2-x
看首尾两个式子,即f[sin(π/2-x)]=sin17(π/2-x);再整体考虑,令t=π/2-x