来自宋广雷的问题
概率论证P(A)>=P(A1)+P(A2)-1,已知A1交A2属于A
概率论证P(A)>=P(A1)+P(A2)-1,已知A1交A2属于A
1回答
2020-05-21 00:06
概率论证P(A)>=P(A1)+P(A2)-1,已知A1交A2属于A
概率论证P(A)>=P(A1)+P(A2)-1,已知A1交A2属于A
P(A1并A2)=P(A1)+P(A2)-P(A1交A2)
P(A)>=P(A1交A2)=P(A1)+P(A2)-P(A1并A2)>=P(A1)+P(A2)-1