来自程敬之的问题
1.y=xarctanx-1/2ln(1+x^2)求dy2.y=tan(3x^2+1)求y的导数即y'3.f(x)=cos^2(a^x+1/x)求导
1.y=xarctanx-1/2ln(1+x^2)求dy2.y=tan(3x^2+1)求y的导数即y'3.f(x)=cos^2(a^x+1/x)求导
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2020-05-20 18:43
1.y=xarctanx-1/2ln(1+x^2)求dy2.y=tan(3x^2+1)求y的导数即y'3.f(x)=cos^2(a^x+1/x)求导
1.y=xarctanx-1/2ln(1+x^2)求dy2.y=tan(3x^2+1)求y的导数即y'3.f(x)=cos^2(a^x+1/x)求导
1.
dy={arctanx+x/(1+x^2)-1/2*[2x/(1+x^2)]}dx
2.
y'=(6x)sec^2(3x^2+1)
3.
f'(x)=2cos(a^x+1/x)*[-sin(a^x+1/x)]*(a^xlna-1/x^2)