来自常继生的问题
f(x)=√3/3sinθ*x^3+cosθ/2*x^2+4x-1,θ是0到5/6派,则f(-1的导数取值范围是?
f(x)=√3/3sinθ*x^3+cosθ/2*x^2+4x-1,θ是0到5/6派,则f(-1
的导数取值范围是?
1回答
2020-05-20 19:10
f(x)=√3/3sinθ*x^3+cosθ/2*x^2+4x-1,θ是0到5/6派,则f(-1的导数取值范围是?
f(x)=√3/3sinθ*x^3+cosθ/2*x^2+4x-1,θ是0到5/6派,则f(-1
的导数取值范围是?
f(-1)的导数很容易求导代入x=-1得到√3sinθ-cosθ+4,它等于2*[(√3)/2*sinθ-1/2*cosθ]+4=2*{[sinθcos(pai/6)]-[cosθsin(pai/6)]}+4=2sin(θ-pai/6)+4,θ∈[0,5/6pai],那么(θ-pai/6)∈[-1/6pai,2/3pai]sin(θ...