来自裴波的问题
【1.设y=2x^3-12x^2+a在[-1,2]上最大值为2,求a2.求由方程ycosx+sin(x-y)=0确定的隐函数y=f(x)的导数y答案是y'=[ysinx-cos(x-y)]/[cosx+cos(x-y)]】
1.设y=2x^3-12x^2+a在[-1,2]上最大值为2,求a2.求由方程ycosx+sin(x-y)=0确定的隐函数y=f(x)的导数y
答案是y'=[ysinx-cos(x-y)]/[cosx+cos(x-y)]
1回答
2020-05-20 11:29