来自贾碧的问题
已知GPS求两点距离C=sin(LatA)*sin(LatB)+cos(LatA)*cos(LatB)*cos(LonA-LonB),已知两点GPS坐标为（LatA,LonA）,（LatB,LonB）,求两点距离为C=sin(LatA)*sin(LatB)+cos(LatA)*cos(LatB)*cos(LonA-LonB),Distance=R*Arccos(C)*Pi/180.
已知GPS求两点距离C=sin(LatA)*sin(LatB)+cos(LatA)*cos(LatB)*cos(LonA-LonB),
已知两点GPS坐标为（LatA,LonA）,（LatB,LonB）,求两点距离为C=sin(LatA)*sin(LatB)+cos(LatA)*cos(LatB)*cos(LonA-LonB),Distance=R*Arccos(C)*Pi/180.第一个公式不理解,
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2020-05-20 18:54