来自梁微的问题
已知y=f(x)是由方程cos(xy)-lny+x=1确定,则limn→∞n(f(2n)−1)=()A.2B.1C.-1D.-2
已知y=f(x)是由方程cos(xy)-lny+x=1确定,则limn→∞n(f(2n)−1)=()
A.2
B.1
C.-1
D.-2
1回答
2020-05-20 20:29
已知y=f(x)是由方程cos(xy)-lny+x=1确定,则limn→∞n(f(2n)−1)=()A.2B.1C.-1D.-2
已知y=f(x)是由方程cos(xy)-lny+x=1确定,则limn→∞n(f(2n)−1)=()
A.2
B.1
C.-1
D.-2
将x=0代入方程得y=f(0)=1,在方程两边求导,得−sin(xy)(y+xy′)−y′y+1=0