来自董静薇的问题
曲线e2x+y-cos(xy)=e-1在点(0,1)处的切线方程为:______.
曲线e2x+y-cos(xy)=e-1在点(0,1)处的切线方程为:______.
1回答
2020-05-20 23:56
曲线e2x+y-cos(xy)=e-1在点(0,1)处的切线方程为:______.
曲线e2x+y-cos(xy)=e-1在点(0,1)处的切线方程为:______.
在等式e2x+y-cos(xy)=e-1两边对x求导,得
e2x+y•(2+y')+sin(xy)•(y+xy')=0
将x=0,y=1代入上式,得到y'(0)=-2.
故所求切线方程为y-1=12