来自刘玠的问题
【(1)-(1/3x+y)+(1/6x-y)=(2)(2s+1)-3(s²-s+2)=(3)-2(a²b-1/4ab²+1/2a³)-(-2a²b+3ab²)=(4)-1/2(5mn-2m²+3n²)+(-3/2mn+2m²+n²/2)=(5)(a³+1/5a²b+3)-1/2(a²b-6)=(6】
(1)-(1/3x+y)+(1/6x-y)=
(2)(2s+1)-3(s²-s+2)=
(3)-2(a²b-1/4ab²+1/2a³)-(-2a²b+3ab²)=
(4)-1/2(5mn-2m²+3n²)+(-3/2mn+2m²+n²/2)=
(5)(a³+1/5a²b+3)-1/2(a²b-6)=
(6)-3(1/2x³-1/3y³+1/6)+2(1/3x³-1/2y³+1/4)=
1回答
2020-05-22 22:14