来自黄绍平的问题
计算:①18.3×0.25+5.3÷0.4-7.13=______;②120043−2003×(20042+2005)=______.
计算:
①18.3×0.25+5.3÷0.4-7.13=______;
②120043−2003×(20042+2005)=______.
1回答
2020-05-24 22:05
计算:①18.3×0.25+5.3÷0.4-7.13=______;②120043−2003×(20042+2005)=______.
计算:
①18.3×0.25+5.3÷0.4-7.13=______;
②120043−2003×(20042+2005)=______.
①18.3×0.25+5.3÷0.4-7.13
=4.575+13.25-7.13
=17.825-7.13
=10.695;
②12004