来自胡旭娟的问题
用克莱姆法则解线性方程组x1+x2-2x3=-32x1+x2-x3=1x1-x2+3x3=8
用克莱姆法则解线性方程组
x1+x2-2x3=-3
2x1+x2-x3=1
x1-x2+3x3=8
1回答
2020-05-30 00:19
用克莱姆法则解线性方程组x1+x2-2x3=-32x1+x2-x3=1x1-x2+3x3=8
用克莱姆法则解线性方程组
x1+x2-2x3=-3
2x1+x2-x3=1
x1-x2+3x3=8
D=
11-2
21-1
1-13
=1
D1=
-31-2
11-1
8-13
=1
D2=
1-3-2
21-1
183
=2
D3=
11-3
211
1-18
=3
所以x1=D1/D=1
x2=D2/D=2
x3=D3/D=3