来自李武朝的问题
求x+y/3+x-y/2=63(x+y)-2(x-y)=28方程组的解{x+y/3+x-y/2=6{3(x+y)-2(x-y)=28求解
求x+y/3+x-y/2=63(x+y)-2(x-y)=28方程组的解
{x+y/3+x-y/2=6
{3(x+y)-2(x-y)=28
求解
1回答
2020-05-29 18:15
求x+y/3+x-y/2=63(x+y)-2(x-y)=28方程组的解{x+y/3+x-y/2=6{3(x+y)-2(x-y)=28求解
求x+y/3+x-y/2=63(x+y)-2(x-y)=28方程组的解
{x+y/3+x-y/2=6
{3(x+y)-2(x-y)=28
求解
x+y/3+x-y/2=6
3(x+y)-2(x-y)=28
2x+2y+3x-3y=36
3x+3y-2x+2y=28
5x-y=36
x+5y=28
5x-y=36
5x+25y=140
26y=104
y=4
x=8