来自刘凤梅的问题
【用换元法解方程组13/x+1+7/y+1=96/x+1+7/2(y+1)=5】
用换元法解方程组13/x+1+7/y+1=96/x+1+7/2(y+1)=5
1回答
2020-05-31 17:47
【用换元法解方程组13/x+1+7/y+1=96/x+1+7/2(y+1)=5】
用换元法解方程组13/x+1+7/y+1=96/x+1+7/2(y+1)=5
令a=1/(x+1),b=1/(y+1)
所以13a+7b=9(1)
6a+7b/2=5(2)
(1)-(2)×2
a=-1
b=22/7
1/(x+1)=-1
x+1=-1
x=-2
1/(y+1)=22/7
y+1=7/22
y=-15/22
所以x=-2,y=-15/22