(1)(1/(x-10))+(1/(x-6))=(1/(X--查字典问答网
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来自陈晓强的问题

  (1)(1/(x-10))+(1/(x-6))=(1/(X-7))+(1/(x-9))(2)((x+1)/(x-2))-((x+2)/(X+3))=(1/(x+7))-(1/(x-6))

  (1)(1/(x-10))+(1/(x-6))=(1/(X-7))+(1/(x-9))

  (2)((x+1)/(x-2))-((x+2)/(X+3))=(1/(x+7))-(1/(x-6))

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2020-05-31 20:57
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高桥茂

  y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)y'={(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)+{(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)'y'(10)={(x-1)(x-2)(x-3)(x-4)(x-5)(x-...

2020-05-31 20:58:55

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