来自姜丁的问题
.(tanx-1)/(tanx+1)=3+2√2.(tanx-1)=(3+2√2)(tanx+1)(2+2√2)tanx=-4-2√2tanx=-√2
.(tanx-1)/(tanx+1)=3+2√2.(tanx-1)=(3+2√2)(tanx+1)(2+2√2)tanx=-4-2√2tanx=-√2
1回答
2020-06-05 17:43
.(tanx-1)/(tanx+1)=3+2√2.(tanx-1)=(3+2√2)(tanx+1)(2+2√2)tanx=-4-2√2tanx=-√2
.(tanx-1)/(tanx+1)=3+2√2.(tanx-1)=(3+2√2)(tanx+1)(2+2√2)tanx=-4-2√2tanx=-√2
tanx-1=(3+2√2)(tanx-1)=(3+2√2)tanx+3+2√2
(2+2√2)tanx=-4-2√2
tanx=(-4-2√2)/(2+2√2)=(-2-√2)/(1+√2)=(-2-√2)(√2-1)=-√2